Proposition 9.19
Given three numbers, to investigate when it is possible to find a fourth proportional to them.
Given three numbers, to investigate when it is possible to find a fourth proportional to them.
Let A, B, C be the given three numbers, and let it be required to investigate when it is possible to find a fourth proportional to them.
Now either they are not in continued proportion, and the extremes of them are prime to one another; or they are in continued proportion, and the extremes of them are not prime to one another; or they are not in continued proportion, nor are the extremes of them prime to one another; or they are in continued proportion, and the extremes of them are prime to one another.
If then A, B, C are in continued proportion, and the extremes of them A, C are prime to one another, it has been proved that it is impossible to find a fourth proportional number to them. [IX. 17]
<*>Next, let A, B, C not be in continued proportion, the extremes being again prime to one another; I say that in this case also it is impossible to find a fourth proportional to them.
For, if possible, let D have been found, so that, as A is to B, so is C to D, and let it be contrived that, as B is to C, so is D to E.
Now, since, as A is to B, so is C to D, and, as B is to C, so is D to E, therefore,
But A, C are prime, primes are also least, [VII. 21] and the least numbers measure those which have the same ratio, the antecedent the antecedent and the consequent the consequent. [VII. 20]
Therefore A measures C as antecedent antecedent.
But it also measures itself; therefore A measures A, C which are prime to one another: which is impossible.
Therefore it is not possible to find a fourth proportional to A, B, C.<*>
Next, let A, B, C be again in continued proportion, but let A, C not be prime to one another.
I say that it is possible to find a fourth proportional to them.
For let B by multiplying C make D; therefore A either measures D or does not measure it.
First, let it measure it according to E; therefore A by multiplying E has made D.
But, further, B has also by multiplying C made D; therefore the product of A, E is equal to the product of B, C; therefore, proportionally, as A is to B, so is C to E; [VII. 19] therefore E has been found a fourth proportional to A, B, C.
Next, let A not measure D; I say that it is impossible to find a fourth proportional number to A, B, C.
For, if possible, let E have been found; therefore the product of A, E is equal to the product of B, C. [VII. 19]
But the product of B, C is D; therefore the product of A, E is also equal to D.
Therefore A by multiplying E has made D; therefore A measures D according to E, so that A measures D.
But it also does not measure it: which is absurd.
Therefore it is not possible to find a fourth proportional number to A, B, C when A does not measure D.
Next, let A, B, C not be in continued proportion, nor the extremes prime to one another.
And let B by multiplying C make D.
Similarly then it can be proved that, if A measures D, it is possible to find a fourth proportional to them, but, if it does not measure it, impossible. Q. E. D.