Proposition I.11
To draw a straight line at right angles to a given straight line from a given point on it.
Let AB
be the given straight line, and C
the given point on it.
Thus it is required to draw from the point C
a straight line at right angles to the straight line AB
.
Let a point D
be taken at random on AC
; 1 let CE
be made equal to CD
; I.3 on DE
let the equilateral triangle FDE
be constructed, I.1 and let FC
be joined;
I say that the straight line FC
has been drawn at right angles to the given straight line AB
from C
the given point on it.
For, since DC
is equal to CE
, and CF
is common,
- the two sides
DC
,CF
are equal to the two sidesEC
,CF
respectively;
and the base DF
is equal to the base FE
;
-
therefore the angle
DCF
is equal to the angleECF
; I.8and they are adjacent angles.
But, when a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right; I.def.10
- therefore each of the angles
DCF
,FCE
is right.
Therefore the straight line CF
has been drawn at right angles to the given straight line AB
from the given point C
on it.
- Q. E. F.
References
Footnotes
-
let CE be made equal to CD.
The verb isκείσθω which, as well as the other parts ofκεῖμαι , is constantly used for the passive ofτίθημι to place
; and the latter word is constantly used in the sense of making, e.g., one straight line equal to another straight line. ↩