Proposition I.11

To draw a straight line at right angles to a given straight line from a given point on it.

Let AB be the given straight line, and C the given point on it.

Thus it is required to draw from the point C a straight line at right angles to the straight line AB.

Let a point D be taken at random on AC; 1 let CE be made equal to CD; I.3 on DE let the equilateral triangle FDE be constructed, I.1 and let FC be joined;

I say that the straight line FC has been drawn at right angles to the given straight line AB from C the given point on it.

For, since DC is equal to CE, and CF is common,

  • the two sides DC, CF are equal to the two sides EC, CF respectively;

and the base DF is equal to the base FE;

  • therefore the angle DCF is equal to the angle ECF; I.8

    and they are adjacent angles.

But, when a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right; I.def.10

  • therefore each of the angles DCF, FCE is right.

Therefore the straight line CF has been drawn at right angles to the given straight line AB from the given point C on it.

  • Q. E. F.

References

graph BT I_11[ I.11 ]:::prop; click I_11 "/elem.1.11" "Book I Proposition 11"; %%%% dependencies I_def10[ I.def.10 ]:::def; click I_def10 "/elem.1.def.10" "Book I Definition 10"; I_1[ I.1 ]:::prop; click I_1 "/elem.1.1" "Book I Proposition 1"; I_3[ I.3 ]:::prop; click I_3 "/elem.1.3" "Book I Proposition 3"; I_8[ I.8 ]:::def; click I_8 "/elem.1.8" "Book I Proposition 8"; %%%% links I_11 --> I_def10 I_11 --> I_1 I_11 --> I_3 I_11 --> I_8 %%%% I_3 dependencies I_2[ I.2 ]:::prop; click I_2 "/elem.1.2" "Book I Proposition 2"; I_post3[ I.ax.3 ]:::post; click I_post3 "/elem.1.post.3" "Book I Postulate 3"; I_def15[ I.def.15 ]:::def; click I_def15 "/elem.1.def.15" "Book I Definition 15"; I_cn1[ I.cn.1 ]:::cn; click I_cn1 "/elem.1.c.n.1" "Book I Common Notion 1"; %%%% links I_3 --> I_2 I_3 --> I_post3 I_3 --> I_def15 I_3 --> I_cn1 %%%% dependencies I_1[ I.1 ]:::prop; click I_1 "/elem.1.1" "Book I Proposition 1"; I_post1[ 1.post.1 ]:::post; click I_post1 "/elem.1.post.1" "Book I Postulate 1"; I_post2[ 1.post.2 ]:::post; click I_post2 "/elem.1.post.2" "Book I Postulate 2"; I_post3[ 1.post.3 ]:::post; click I_post3 "/elem.1.post.3" "Book I Postulate 3"; I_def15[ 1.def.15 ]:::def; click I_def15 "/elem.1.def.15" "Book I Definition 15"; %%%% links I_2 --> I_1 I_2 --> I_post1 I_2 --> I_post2 I_2 --> I_post3 I_2 --> I_def15

Footnotes


  1. let CE be made equal to CD.
    The verb is κείσθω which, as well as the other parts of κεῖμαι, is constantly used for the passive of τίθημι to place ; and the latter word is constantly used in the sense of making, e.g., one straight line equal to another straight line.